If the electromagnetic field F_{ab} satisfies Maxwell's equations
\begin{equation*}
\nabla_{[a}F_{bc]}= 0 \quad\text{and}\quad \nabla^a F_{ab} =0
\end{equation*}
and there is a spinor \psi such that
\begin{equation}\label{eq:20161115b}
(\nabla_{\mu} + i \sqrt{4 \pi} \not F \gamma_{\mu} ) \psi = 0
\end{equation}
and i \bar \psi \gamma^{\mu} \psi is time-like
then the Einstein equations are satisfied as well:
\begin{equation*}
R_{\mu\nu} - \frac{1}{2} R g_{\mu\nu} = 8 \pi T_{\mu\nu}
\end{equation*}
Property A is proved by using the equation \begin{equation} \gamma^{\nu}[\hat\nabla_{\mu}, \hat\nabla_{\nu}]\psi = 0 \end{equation} I therefore calculated this commutator for the ansatz \eqref{eq:20161205a}. The result is [3] \begin{align} \gamma^{\nu}[\hat\nabla_{\mu}, \hat\nabla_{\nu}]\psi = \Big(& -\frac{1}{2} R_{i \mu} \gamma^{i} + \frac{1}{8} (- D + 5 - 4 \theta) V_{\mu} +(\frac{1}{2} - 2 \theta^2 - \frac{\theta}{2} D + 2 \theta) III_{\mu} + ( 2 \theta^2 + \frac{D-3}{2} ) I_{\mu} \nonumber \\ & + \frac{D-3}{4} F^2 \gamma_{\mu} -\frac{1}{2} \nabla_i F^{ij} \gamma_{j \mu} + \theta \nabla_j F^j_{\ \ \mu} \label{eq:20161205b}\\ & -\frac{1}{4} \nabla^{\nu} F^{ij} \gamma_{\nu ij \mu} - (\frac{3}{4} - \frac{D}{4} -\theta ) \nabla_{\mu}F^{kj} \gamma_{kj} - \theta \nabla_k F_{\mu j} \gamma^{kj}\Big) \psi \nonumber \end{align} with \begin{align*} I_{\mu} &= (F^2)_{\mu}^{\ \ i}\gamma_i\\ III_{\mu} &= F_{\mu}^{\ \ i} F^{jk} \gamma_{ijk}\\ V_{\mu} &= F^{ij}F^{kl} \gamma_{\mu ijkl} \end{align*} If I now assume that \nabla_{[ i } F_{jk ]} =0 then the last three terms in \eqref{eq:20161205b} combine to \begin{equation*} ( \frac{3}{4} - \frac{D}{4} - \theta + \frac{\theta}{2} )\nabla_{\mu} F^{kj} \gamma_{kj} \end{equation*} This is zero if I set \theta = \dfrac{3 - D}{2}. This agrees with the special case D=4 [4]. For this value of \theta, I can simplify expression \eqref{eq:20161205a}. The result is \begin{align} \gamma^{\nu}[\hat\nabla_{\mu}, \hat\nabla_{\nu}]\psi = \Big(& -\frac{1}{2} R_{i \mu} \gamma^{i} + \frac{D-1}{8} V_{\mu} -\frac{1}{4} (D-1) (D-4) III_{\mu} -\frac{1}{2} (D-2) (D-3) ( T_{\mu i} - \frac{T} {D-2} \eta_{\mu i} ) \gamma^i\nonumber \\ & -\frac{1}{2} \nabla_i F^{ij} \gamma_{j \mu} -\frac{D-3}{2} \nabla_j F^j_{\ \ \mu}\Big) \psi \nonumber \end{align} with T_{\mu\nu} the electromagnetic stress tensor \begin{align*} T_{\mu\nu} &= - ( F_{\mu \alpha} F^{\alpha}_{\ \ \nu} + \frac{1}{4} \eta_{\mu\nu} F^2)\\ T &= T_{\mu}^{\ \mu} \end{align*} For general D, the terms V_{\mu} and III_{\mu} survive and the commutator \gamma^{\nu}[\hat\nabla_{\mu}, \hat\nabla_{\nu}]\psi contains terms that are not zero if the fields satisfy the equations of motion. I conclude that for general dimension D, I cannot use a generalization of property A to obtain a generalization of the IWP black holes. For D=4, V_{\mu}= 0 and the coefficient of III_{\mu} is zero, hence property A follows. Something can also be salvaged in D=5, this is the subject of another post. Of course, I can also force the terms involving V_{\mu} and III_{\mu} to zero, then I get the following property (after rescaling of the electromagnetic field)
If the electromagnetic field F_{ab} satisfies Maxwell's equations
\begin{equation*}
\nabla_{[a}F_{bc]}= 0 \quad\text{and}\quad \nabla^a F_{ab} =0
\end{equation*}
and
F_{\mu}^{\ \ [i} F^{jk]} =0
and there is a spinor \psi such that
\begin{equation}
\left(\nabla_{\mu} + i \sqrt{ \frac{8 \pi}{(D-2)(D-3)}} \left( F^{ij}\gamma_{ij\mu} + \frac{D-3}{2} F_{\mu}^{\ \ j}\gamma_j \right)\right) \psi =0
\end{equation}
and i \bar \psi \gamma^{\mu} \psi is time-like
then the Einstein equations are satisfied as well:
\begin{equation*}
R_{\mu\nu} - \frac{1}{2} R g_{\mu\nu} = 8 \pi T_{\mu\nu}
\end{equation*}
References and comments
[1] Black hole solutions in string theory, Maeda and Nozawa, 2011, hep-th/1104.1849
[2] See the previous blog post for the notation that I use.
[3] In D=4, the result can be found in [1], where it is said that is "a simple exercise". However, I found the calculation very tedious and it took me a long time to calculate the commutator for general dimension D. There are many manipulations one can do with gamma matrices, but I think that the calculation proceeds in the most efficient way if I use the commutators \begin{align*} [\gamma_i , \gamma_j] &= 2 \gamma_{ij}\\ [\gamma_i , \gamma_{jkl}] &= 2 \gamma_{ijkl}\\ [\gamma^{ijk} , \gamma_{abc}] &= 2 \gamma^{ijk}_{\quad \ abc} - 36 \delta^{[i}_{[a}\delta^{j}_{b} \gamma^{k]}_{\ \ \ c]} \end{align*}
[4] My result is similar to, but different from, equation A10 in hep-th/1104.1849
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