#### Introduction

Mertens says he will prove the formulas$$\sum_{ p \le x } \frac{1}{p}= \log\log x + C$$ and $$\prod_{ p \le x } \frac{1}{1 – \frac{1}{p}} = C’ \log x$$ The sum and the product are over primes \( p \). Mertens will also calculate the constants \( C\) and \( C’\). Mertens also says that the formulas are already in a paper by Chebyshev, but with doubtful proof. These formulas are now known as Mertens theorems.

#### Section 1

Mertens proves that \( \theta(x) < 2 x \); he says that Chebyshev gives a sharper bound which he does not need. Along the way Mertens also proves that \( \psi(x) < 2 x \). I found Mertens reasoning easy to follow because it is an easy version of the reasoning of a (later) paper by Ramanujan that I read. Ramanujan's reasoning is more involved because he proves a stronger result, namely Bertrand's postulate.#### Section 2

In this section Mertens proves that \( \sum_{ p \le x } \frac{\log p}{p} = \log x + R \) with \( | R | < 2 \). This statement is now known as Mertens first theorem. The proof takes less than a page, and only uses elementary inequalities. The proof is easy to read; in the middle I found a bit of help in this paper from Mark Villarino.Here are some graphs illustrating this theorem.

In the graph below I illustrate that the difference is indeed less than 2.

## No comments:

## Post a Comment